The hydroelectric power plant having flow rate 1000 cubic meter/s and 800 m high head having plant efficiency of 96% will generate how many kilowatts | Power Generation MCQ

The hydroelectric power plant having flow rate 1000 m³/s and 800 m high head having an efficiency of 90% will generate how many kilowatts:

1. 6.93E+06
2. 7.53E+06
3. 9.22E+05
4. 5.87E+05

Correct answer: 2. 7.53E+06

Explanation: From generation capacity formula of the hydroelectric power plant:

P = 9.8 * ηQH

where

P = Power (kilowatts) ; η = plant efficiency ; Q = discharge flow rate ( m³/s ); H = head (m)

P = 9.8 * 0.9 * 800 * 1000 = 7.53E+06