The temperature at which resistance of conductors becomes double to its resistance at 0°C is:
- 1/α0 °C
- 3/α0 °C
- 1/(1+ α0) °C
- α0 °C
Correct answer: 1. 1/α0 °C
Explanation
Rt= R0 (1+ α0 t)
Here it is known that
Rt= 2.R0
2R0= R0 (1+ α0 t)
Or t = 1/α0°C