A 220 V DC motor having armature resistance of 0.7 Ω and back emf of 190 V will draw current:
- 36.92 A
- 42.85 A
- 53.64 A
- 68.55 A
Correct answer: 2. 42.85 A
Explanation: Current drawn = (V – Eb)/R = (220 – 190) / 0.7 Ω = 42.85 A
So a 220 V DC motor having armature resistance of 0.7 Ω and back emf of 190 V will draw current 42.85 Amps of current