If Ie=205 mA, Ic=203 mA, the beta dc is | Basic Electronics MCQ
If Ie=205 mA, Ic=203 mA, the beta dc is (approx): 200 100 50 25 Correct answer: 2. 100 Explanation: From formula: Ib= Ie – Ic = 205 – 203 = 2 mA Beta dc = Ic / Ib = 203 / 2 = 101.5 ≈ 100