If Ie=205 mA, Ic=203 mA, the beta dc is | Basic Electronics MCQ

If I_e=205 mA, I_c=203 mA, the beta dc is (approx):

1. 200
2. 100
3. 50
4. 25

Correct answer: 2. 100

Explanation:

From formula: I_b= I_e – I_c = 205 – 203 = 2 mA

Beta dc = I_c / I_b = 203 / 2 = 101.5 ≈ 100