If the insulation resistance of cable of length 10 km is 1 MΩ its insulation resistance for 70 km will be:
- 0.255 MΩ
- 0.556 MΩ
- 0.714 MΩ
- 0.955 MΩ
Correct answer: 3. 0.714 MΩ
For Case 1: R1 ∝ 1/L1 ; R2 ∝ 1/L2
R2/R1 = L1/L2
R2 = R1 * L1/L2 = 5 * 10 / 70 = 0.714 MΩ