MCQ#1
A 30 HP, 6 pole, 60 Hz slip ring induction motor runs at 940 RPM at full load. The mechanical losses are around 2000 W, while the copper losses in short-circuiting gear are 200 W. The total mechanical output of the motor is:
- 22380 W
- 24580 W
- 48750 W
- 52500 W
Correct answer: 2. 24580 W
Output in watts = 30 * 746 = 22380 W
Total mechanical output = 22380 W + 200 W + 2000 W = 24580 W