The full-load copper loss of a transformer is 3200 W. At half-load the copper loss will be:
- 6400 W
- 1600 W
- 800 W
- 400 W
Correct answer: 3. 800 W
Explanation: Copper losses = I2 R
At half load the current becomes half
Copper losses at half load = (I/2)2 R = I2/4 . R = 1/4 ( I2 R ) = 3200 / 4 = 800 watts