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Top 10 Current Divider Rule MCQ Problems

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Basic Electrical Engineering MCQ Questions on Current divider rule.

SI unit of current is

SI unit of current is:

  1. volts
  2. ohms
  3. watts
  4. amps

Correct answer: 4. amps

Current always divide in

Current always divides in:

  1. Series
  2. Parallel

Correct answer: 2. Parallel

Current divider rule is applicable on

Current divider rule is applicable on:

  1. Series circuits
  2. Parallel circuits

Correct answer: 2. Parallel

For two parallel resistors having same resistance the current will

For two parallel resistors having same resistance the current will:

  1. Remain same
  2. Divide

Correct answer: 1. Remain same

Which of the following is correct formula for current divider

Which of the following is correct formula for current divider:

  1. Ix = (Rx/Req) * It
  2. Ix = (Req/Rx) * It
  3. Both of these
  4. None of these

Correct answer: 2. Ix = (Req/Rx) * It

Current Divider Rule MCQ#6

For current divider circuit give below, if R1 = R2 then:

  1. I1 > I2
  2. I1 < I2
  3. I1 = I2
  4. Insufficient data

Correct answer: 3. I1 = I2

Current Divider Rule MCQ#7

For the same circuit given in problem 6, if R1 > 10R2, for any value of source current, the majority of current will flow through:

  1. R1
  2. R2

Correct answer: 1. R2

Current Divider Rule MCQ#8

Current divider rule is never applied to series circuits because:

  1. It requires application of very complex formulae
  2. Current never divides in series

Correct answer: 2. Current never divides in series

Current Divider Rule MCQ#9

For current divider circuit in problem 6, If Is = 2 A and R1 = 3 Ω and R2 = 2 Ω and I1 and I2 are values of currents flowing through R1 and R2, then:

  1. I1 = 1.2 Ω, I2 = 0.8 Ω
  2. I1 = 1.5 Ω, I2 = 0.5 Ω
  3. I1 = 1.3 Ω, I2 = 0.7 Ω
  4. I1 = 0.8 Ω, I2 = 1.2 Ω

Correct answer: 4. I1 = 0.8 Ω, I2 = 1.2 Ω

Current Divider MCQ#10

For circuit given in problem 6, if another resistor is added in series to R2, the current flowing through R1 will:

  1. Increase
  2. Decrease
  3. Remain same

Correct answer: 1. Increase

By increasing resistance there will be reduction of current in R2. To understand this Consider initially current source is of 5A and resistor R1 is of 2 ohms, while R2 is also 2 ohms.

Now current across R1 is: 2.5 A; (I1 = (Req/R1) * It = (1/2) * 5 A = 2.5 A

Now suppose another resistor (having resistance 1 ohms is added in series to R2. Now current across R1:

I1 = (Req/R1) * It = (1.2/2) * 5 A = 3 A

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