Certain Steam Power Station has an annual load factor of 45%. If the maximum demand is 25000 kW, then units generated in annum are:
- 3.44*105 kWh
- 9.86*107 kWh
- 8.76*106 kWh
- 10.92*107 kWh
Correct answer: 2. 9.86*107 kWh
Explanation:
Formula: Generated units/annum = Maximum demand * Hours in a year * L.F
= 25,000 * 8760 * 0.4