Transistor Biasing MCQ with Explanatory Answers

Electrical Engineering multiple choice questions on Transistor Biasing.

Transistor biasing represents the use of which condition

Transistor biasing represents the use of:

1. AC conditions
2. DC conditions
3. Both of above
4. None of above

Correct answer: 2. DC conditions

The terms biasing a transistor means the use of DC voltage for establishing the certain operating conditions in a transistor

What does operating point or Q point represent in Transistor Bias

The operating point or Q point represents:

1. Peak values of the sine wave
2. Zero signal values of I_C and V_CE
3. Values at which I_C is maximum and V_CE is minimum
4. Values at which I_C is minimum and V_CE is maximum

Correct answer: 2. Zero signal values of I_C and V_CE

Proper amplification of Silicon diode by transistor circuit

For proper amplification by a transistor circuit, what should be the value of V_BE for a silicon diode should:

1. Be Zero
2. Be as low as possible
3. Not fall below 0.7 V
4. Be greater than 1.4 V and lesser than 2.8 V

Correct answer: 3. Not fall below 0.7 V

For proper amplification by a transistor circuit, what should be the value of V_BE for a silicon diode should not fall below 0.7 V

Which of the following is correct about operating point and the A.C load line

Which of the following is correct about operating point and the A.C load line:

1. The operating point lies on load line
2. The operating point doesn’t lie on load line
3. The operating point may or may not lie on load line

Correct answer: 1. The operating point lies on load line

Voltage Divider Bias Numerical Problem

In a voltage divider bias circuit following data is known:

V_CC = 20 V; R₁ = 5k ohm; R₂ = 1k ohm; R_C = 3.6k ohm; R_E = 1k ohm

What is the value of emitter voltage:

1. 1.55 V
2. 2.63 V
3. 4.8 V
4. 5.55 V

Correct answer: 2. 2.63 V

Solution: V₂ = {(V_CC)/(R₁ + R₂ ) } * R₂

= (20/6)*1 = 3.33 V

Emitter voltage = V₂ – V_BE = 3.33 – 0.7 = 2.63 V