two-series-resistors-of-5-and-10-ohms-are-connected-in-parallel-to-two-series-resistors-of-10-and-5-ohms-find-the-current-across-r2

Two series resistors of 5 and 10 ohms are connected in parallel to two series resistors of 10 and 5 ohms. Find the current across R2 | Basic Electrical Engineering MCQ#17

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Two series resistors of 5 and 10 ohms are connected in parallel to two series resistors of 10 and 5 ohms. Find the current across R2.

two-series-resistors-of-5-and-10-ohms-are-connected-in-parallel-to-two-series-resistors-of-10-and-5-ohms-find-the-current-across-r2

Solution:

Ra = R1 + R2 = 15 ohms

Rb = R3 + R4 = 15 ohms

Using current divider rule, the current across Ra is:

Ia = 5 A.

Since both resistors are in series, both have 5 amps current flowing through them.

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