Two series resistors of 5 and 10 ohms are connected in parallel to two series resistors of 10 and 5 ohms. Find the current across R2.
Ra = R1 + R2 = 15 ohms
Rb = R3 + R4 = 15 ohms
Using current divider rule, the current across Ra is:
Ia = 5 A.
Since both resistors are in series, both have 5 amps current flowing through them.