Parallel Circuit analysis MCQ Questions.
Parallel Circuit analysis MCQ#1
Consider the circuit given below and then answer the questions provided below:
Equivalent resistance Example
What is equivalent resistance of circuit:
- 2k ohm
- 6k ohm
- 10k ohm
- 15k ohm
Correct answer: 2. 6k ohm
Req = 1/(1/R1 + 1/R2) = 1/(1/10 + 1/15) = 6k ohm
Learn More examples on parallel circuits here
Find current across R1
The current across resistor R1 is:
- 1 mA
- 2 mA
- 5 mA
- 10 mA
Correct answer: 2. 2 mA
You can use Ohm’s law: I =V/R = 20/10 kohm = 2 mA
OR alternatively you can use current divider rule
Find current across R2
The current across resistor R2 is:
- 1.33 mA
- 5 mA
- 13.44 mA
- 25.8 mA
Correct answer: 1. 1.33 A
Solution: From Ohm’s Law: I = V/R = 20/15k = 1.33 mA
Find total incoming current
What is value of It:
- 1.33 mA
- 2 mA
- 3.33 mA
- None of the above
Correct answer: 3. 3.33 mA
Solution: There are two methods that can be used
By directly Using Ohm’s law:
I = V/Req = 20 V/6k = 3.33 A
OR use Ohm’s law to find individual currents (as we did earlier) and then use Kirchoff’s current law to find equivalent resistance.
Find power consumed by R1
What is total power consumed by R1:
- 10 mW
- 20 mW
- 30 mW
- 40 mW
Correct answer: 4. 40 mW
Formula:
P = V2/R = (20)2/10k = 400/10k = 40 mW
Find power consumed by R2
What is total power consumed by R2:
- 6.66 mW
- 16.66 mW
- 26.66 mW
- 36.66 mW
Correct answer: 3. 26.66 mW
Formula:
P = V2/R = (20)2/15k = 400/15k = 26.66 mW
Find power delivered by Voltage source
Find total power delivered by voltage source:
- 35 mW
- 60 mW
- 66.66 mW
- None of the above
Correct answer: 3. 66.66 mW
Total power = Sum of powers dissipated = 40 + 26.66 = 66.66 mW